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roger stafford received badge for on 2 nov 2018 |
roger stafford submitted to on 27 feb 2012 |
roger stafford submitted a to yes, you are right s l, a direct brute force summation is surely not the most efficient method of determining the sums of these series. you are the only one so far with a valid solution that met the 50*eps tests. in fact your answers are very much closer than that to mine, within a few eps. however, there is another single analytic function that can be used which is much simpler and would undoubtedly give you a lower "size" than 92 if you or others can find it. r. stafford
on 26 feb 2012 |
roger stafford submitted to on 26 feb 2012 |
roger stafford submitted to on 25 feb 2012 |
roger stafford submitted to on 25 feb 2012 |
roger stafford submitted a to i am pleased that you solved this problem, david. congratulations! i didn't find any particularly easier way of solving it. the crucial step is showing that the probability density is proportional to your 1/y^3 for points within the corresponding "kite-shaped region". i used the jacobian between two coordinate systems to show that. after dividing that region into two halves everything falls into place, though in my dotage i had to make heavy use of the symbolic toolbox to check for errors. (i hope this problem will serve as a warning to people who recommend this method of producing random numbers with a predetermined sum.) r. stafford
on 24 feb 2012 |
roger stafford submitted a to it is inherent in the definition of p here that the density, dp/da, must increase as p increases and therefore da/dp must decrease. in your proposed solution you have da/dp increasing as p increases. r. stafford
on 23 feb 2012 |
roger stafford received badge for on 23 feb 2012 |
roger stafford submitted to on 17 feb 2012 |
roger stafford submitted to on 9 feb 2012 |
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roger stafford submitted to on 8 feb 2012 |
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roger stafford submitted to on 7 feb 2012 |
roger stafford submitted to on 7 feb 2012 |
roger stafford submitted to on 6 feb 2012 |
roger stafford submitted to on 6 feb 2012 |
roger stafford submitted to on 6 feb 2012 |
roger stafford submitted to on 6 feb 2012 |
roger stafford submitted to on 5 feb 2012 |
roger stafford submitted to on 5 feb 2012 |
roger stafford submitted to on 2 feb 2012 |
roger stafford received badge for on 2 feb 2012 |
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roger stafford submitted to on 30 jan 2012 |
roger stafford submitted to on 30 jan 2012 |
roger stafford submitted to on 29 jan 2012 |
roger stafford submitted to on 29 jan 2012 |
roger stafford submitted to on 29 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 28 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 27 jan 2012 |
roger stafford submitted to on 26 jan 2012 |
roger stafford submitted to on 26 jan 2012 |