partition data for cross-凯发k8网页登录

use the cross-validation misclassification error to estimate how a model will perform on new data.

load the ionosphere data set. create a table containing the predictor data x and the response variable y.

load ionosphere
tbl = array2table(x);
tbl.y = y;

use a random nonstratified partition hpartition to split the data into training data (tbltrain) and a reserved data set (tblnew). reserve approximately 30 percent of the data.

rng('default') % for reproducibility
n = length(tbl.y);
hpartition = cvpartition(n,'holdout',0.3); % nonstratified partition
idxtrain = training(hpartition);
tbltrain = tbl(idxtrain,:);
idxnew = test(hpartition);
tblnew = tbl(idxnew,:);

train a support vector machine (svm) classification model using the training data tbltrain. calculate the misclassification error and the classification accuracy on the training data.

mdl = fitcsvm(tbltrain,'y');
trainerror = resubloss(mdl)

trainerror = 0.0569

trainaccuracy = 1-trainerror

trainaccuracy = 0.9431

typically, the misclassification error on the training data is not a good estimate of how a model will perform on new data because it can underestimate the misclassification rate on new data. a better estimate is the cross-validation error.

create a partitioned model cvmdl. compute the 10-fold cross-validation misclassification error and classification accuracy. by default, crossval ensures that the class proportions in each fold remain approximately the same as the class proportions in the response variable tbltrain.y.

cvmdl = crossval(mdl); % performs stratified 10-fold cross-validation
cvtrainerror = kfoldloss(cvmdl)

cvtrainerror = 0.1220

cvtrainaccuracy = 1-cvtrainerror

cvtrainaccuracy = 0.8780

notice that the cross-validation error cvtrainerror is greater than the resubstitution error trainerror.

classify the new data in tblnew using the trained svm model. compare the classification accuracy on the new data to the accuracy estimates trainaccuracy and cvtrainaccuracy.

newerror = loss(mdl,tblnew,'y');
newaccuracy = 1-newerror

newaccuracy = 0.8700

the cross-validation error gives a better estimate of the model performance on new data than the resubstitution error.

use the same stratified partition for 5-fold cross-validation to compute the misclassification rates of two models.

load the fisheriris data set. the matrix meas contains flower measurements for 150 different flowers. the variable species lists the species for each flower.

load fisheriris

create a random partition for stratified 5-fold cross-validation. the training and test sets have approximately the same proportions of flower species as species.

rng('default') % for reproducibility
c = cvpartition(species,'kfold',5);

create a partitioned discriminant analysis model and a partitioned classification tree model by using c.

discrcvmodel = fitcdiscr(meas,species,'cvpartition',c);
treecvmodel = fitctree(meas,species,'cvpartition',c);

compute the misclassification rates of the two partitioned models.

discrrate = kfoldloss(discrcvmodel)

discrrate = 0.0200

treerate = kfoldloss(treecvmodel)

treerate = 0.0333

the discriminant analysis model has a smaller cross-validation misclassification rate.

observe the test set (fold) class proportions in a 5-fold nonstratified partition of the fisheriris data. the class proportions differ across the folds.

load the fisheriris data set. the species variable contains the species name (class) for each flower (observation). convert species to a categorical variable.

load fisheriris
species = categorical(species);

find the number of observations in each class. notice that the three classes occur in equal proportion.

c = categories(species) % class names

c = 3x1 cell
    {'setosa'    }
    {'versicolor'}
    {'virginica' }

numclasses = size(c,1);
n = countcats(species) % number of observations in each class

n = 3×1
    50
    50
    50

create a random nonstratified 5-fold partition.

rng('default') % for reproducibility
cv = cvpartition(species,'kfold',5,'stratify',false) 

cv = 
k-fold cross validation partition
   numobservations: 150
       numtestsets: 5
         trainsize: 120  120  120  120  120
          testsize: 30  30  30  30  30

show that the three classes do not occur in equal proportion in each of the five test sets, or folds. use a for-loop to update the ntestdata matrix so that each entry ntestdata(i,j) corresponds to the number of observations in test set i and class c(j). create a bar chart from the data in ntestdata.

numfolds = cv.numtestsets;
ntestdata = zeros(numfolds,numclasses);
for i = 1:numfolds
    testclasses = species(cv.test(i));
    ncounts = countcats(testclasses); % number of test set observations in each class
    ntestdata(i,:) = ncounts';
end
bar(ntestdata)
xlabel('test set (fold)')
ylabel('number of observations')
title('nonstratified partition')
legend(c)

notice that the class proportions vary in some of the test sets. for example, the first test set contains 8 setosa, 13 versicolor, and 9 virginica flowers, rather than 10 flowers per species. because cv is a random nonstratified partition of the fisheriris data, the class proportions in each test set (fold) are not guaranteed to be equal to the class proportions in species. that is, the classes do not always occur equally in each test set, as they do in species.

create a nonstratified holdout partition and a stratified holdout partition for a tall array. for the two holdout sets, compare the number of observations in each class.

when you perform calculations on tall arrays, matlab® uses either a parallel pool (the default if you have parallel computing toolbox™) or the local matlab session. to run the example using the local matlab session when you have parallel computing toolbox, change the global execution environment by using the function.

mapreducer(0)

create a numeric vector of two classes, where class 1 and class 2 occur in the ratio 1:10.

group = [ones(20,1);2*ones(200,1)]

group = 220×1
     1
     1
     1
     1
     1
     1
     1
     1
     1
     1
      ⋮

create a tall array from group.

tgroup = tall(group)

tgroup =
  220x1 tall double column vector
     1
     1
     1
     1
     1
     1
     1
     1
     :
     :

holdout is the only cvpartition option that is supported for tall arrays. create a random nonstratified holdout partition.

cv0 = cvpartition(tgroup,'holdout',1/4,'stratify',false)  

cv0 = 
hold-out cross validation partition
   numobservations: [1x1 tall]
       numtestsets: 1
         trainsize: [1x1 tall]
          testsize: [1x1 tall]

return the result of cv0.test to memory by using the gather function.

testidx0 = gather(cv0.test);

evaluating tall expression using the local matlab session:
- pass 1 of 1: completed in 0.27 sec
evaluation completed in 0.39 sec

find the number of times each class occurs in the test, or holdout, set.

accumarray(group(testidx0),1) % number of observations per class in the holdout set

ans = 2×1
     5
    51

cvpartition produces randomness in the results, so your number of observations in each class can vary from those shown.

because cv0 is a nonstratified partition, class 1 observations and class 2 observations in the holdout set are not guaranteed to occur in the same ratio as in tgroup. however, because of the inherent randomness in cvpartition, you can sometimes obtain a holdout set in which the classes occur in the same ratio as in tgroup, even though you specify 'stratify',false. because the training set is the complement of the holdout set, excluding any nan or missing observations, you can obtain a similar result for the training set.

return the result of cv0.training to memory.

trainidx0 = gather(cv0.training);

evaluating tall expression using the local matlab session:
- pass 1 of 1: completed in 0.1 sec
evaluation completed in 0.14 sec

find the number of times each class occurs in the training set.

accumarray(group(trainidx0),1) % number of observations per class in the training set

ans = 2×1
    15
   149

the classes in the nonstratified training set are not guaranteed to occur in the same ratio as in tgroup.

create a random stratified holdout partition.

cv1 = cvpartition(tgroup,'holdout',1/4)  

cv1 = 
hold-out cross validation partition
   numobservations: [1x1 tall]
       numtestsets: 1
         trainsize: [1x1 tall]
          testsize: [1x1 tall]

return the result of cv1.test to memory.

testidx1 = gather(cv1.test);

evaluating tall expression using the local matlab session:
- pass 1 of 1: completed in 0.064 sec
evaluation completed in 0.084 sec

find the number of times each class occurs in the test, or holdout, set.

accumarray(group(testidx1),1) % number of observations per class in the holdout set

ans = 2×1
     5
    51

in the case of the stratified holdout partition, the class ratio in the holdout set and the class ratio in tgroup are the same (1:10).

create a random partition of data for leave-one-out cross-validation. compute and compare training set means. a repetition with a significantly different mean suggests the presence of an influential observation.

create a data set x that contains one value that is much greater than the others.

x = [1 2 3 4 5 6 7 8 9 20]';

create a cvpartition object that has 10 observations and 10 repetitions of training and test data. for each repetition, cvpartition selects one observation to remove from the training set and reserve for the test set.

c = cvpartition(10,'leaveout')

c = 
leave-one-out cross validation partition
   numobservations: 10
       numtestsets: 10
         trainsize: 9  9  9  9  9  9  9  9  9  9
          testsize: 1  1  1  1  1  1  1  1  1  1

apply the leave-one-out partition to x, and take the mean of the training observations for each repetition by using crossval.

values = crossval(@(xtrain,xtest)mean(xtrain),x,'partition',c)

values = 10×1
    6.5556
    6.4444
    7.0000
    6.3333
    6.6667
    7.1111
    6.8889
    6.7778
    6.2222
    5.0000

view the distribution of the training set means using a box chart (or box plot). the plot displays one outlier.

boxchart(values)

find the repetition corresponding to the outlier value. for that repetition, find the observation in the test set.

[~,repetitionidx] = min(values)

repetitionidx = 10

observationidx = test(c,repetitionidx);
influentialobservation = x(observationidx)

influentialobservation = 20

training sets that contain the observation have substantially different means from the mean of the training set without the observation. this significant change in mean suggests that the value of 20 in x is an influential observation.